Solution Electrical Numerical 14

Numerical 14: 72 KVA transformer supplies a heating and lighting load of 12 KW at unity power factor and a motor load of 70 kVA at 0.766 (lagging) power factor; Calculate the minimum rating of the power-factor improvement capacitors which must be connected in the circuit the ensure that the transformer does not become overloaded.
Solution: 
Motor:-
KVA = 70
CosΦ = 0.766
∴ Φ = 40°
SinΦ = 0.6428
KVAr = KVA X SinΦ = 70 x 0.6428 = 44.996
KW = KVA x CosΦ = 70 x 0.766 =53.62

Transformer:-
KVA = 72
KW = Total Load applied = 12 + 53.62 =65.62
$\displaystyle \mathrm{KVAr = \sqrt{72^{2}-65.62^{2}}}$ 
=29.63

Capacitor 
KVAr = 44.996 - 29.63 =15.4

Comments

  1. Mistake in formula kvar= Sq root 72sq- 65sq

    ReplyDelete
    Replies
    1. Dear Unknown, Thankyou for mentioning the error. The required correction is made. Please keep posting your valuable comments.

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  2. How the reactive power of motor and reactive power transformer is minuses ( 44.989- 29.86) what is formula I don't understand this step

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  3. If also mention the formula it will helpful

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