Solution Naval Numerical 21

Numerical 21. With the aid of sketches: a. Explain various lines plan. b. The half -breadths of water plane of a ship of 120m length ad 15m breadth are given below:b. The half -breadths of water plane of a ship of 120m length ad 15m breadth are given below:Station 0 1 2 3 4 5 6 7 8. Half breadths 1.6 2.8 5.5 6.4 7.3 6.2 4.2 2.0 0 Calculate i) Water plane area ii) TPC in salt water iii) Cw iv) LCF from Mid-ship.

Solution: (a)(b)
Half breadth
SM
PRODUCT
For area
LEVER from
Aft station
PRODUCT
For moment
1.6
1
1.6
0
0
2.8
4
11.2
1
11.2
5.5
2
11
2
22
6.4
4
25.6
3
76.8
7.3
2
14.6
4
58.4
6.2
4
24.8
5
99.2
4.2
2
8.4
6
50.4
2.0
4
8
7
56
0
1
0
8
0


∑a = 105.2

∑i = 374


Common interval (h) = 120/8 = 15
(i) Area of water plane  (Aw) = 2 x (h/3) x ∑a
= 2 x (15/3) x 105.2
= 1052 m-sq.
(ii) TPC = Aw x ρ /100 = 1052 x 1.025 /100 = 10.782 tonne.
(iii) Cw = Aw/LxB = 1052 /(120 x 15) =0.584
(iv) LCF from mid ship = (L/2) - LCF from Aft station
= (L/2) - h x (∑i/∑a)
= 60 - 15 x 374/105.2
= 60 - 53.327
= 6.673m aft of mid ship


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